Optimal. Leaf size=192 \[ \frac {a F_1\left (\frac {1}{2};\frac {1}{2} (-1+n),1;\frac {3}{2};\sin ^2(e+f x),\frac {a^2 \sin ^2(e+f x)}{a^2-b^2}\right ) \cos (e+f x) \cos ^2(e+f x)^{\frac {1}{2} (-1+n)} (d \sec (e+f x))^n \sin (e+f x)}{\left (a^2-b^2\right ) f}-\frac {b F_1\left (\frac {1}{2};\frac {n}{2},1;\frac {3}{2};\sin ^2(e+f x),\frac {a^2 \sin ^2(e+f x)}{a^2-b^2}\right ) \cos ^2(e+f x)^{n/2} (d \sec (e+f x))^n \sin (e+f x)}{\left (a^2-b^2\right ) f} \]
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Rubi [A]
time = 0.22, antiderivative size = 192, normalized size of antiderivative = 1.00, number of steps
used = 6, number of rules used = 4, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.174, Rules used = {3954, 2902,
3268, 440} \begin {gather*} \frac {a \sin (e+f x) \cos (e+f x) \cos ^2(e+f x)^{\frac {n-1}{2}} (d \sec (e+f x))^n F_1\left (\frac {1}{2};\frac {n-1}{2},1;\frac {3}{2};\sin ^2(e+f x),\frac {a^2 \sin ^2(e+f x)}{a^2-b^2}\right )}{f \left (a^2-b^2\right )}-\frac {b \sin (e+f x) \cos ^2(e+f x)^{n/2} (d \sec (e+f x))^n F_1\left (\frac {1}{2};\frac {n}{2},1;\frac {3}{2};\sin ^2(e+f x),\frac {a^2 \sin ^2(e+f x)}{a^2-b^2}\right )}{f \left (a^2-b^2\right )} \end {gather*}
Antiderivative was successfully verified.
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Rule 440
Rule 2902
Rule 3268
Rule 3954
Rubi steps
\begin {align*} \int \frac {(d \sec (e+f x))^n}{a+b \sec (e+f x)} \, dx &=\left (\cos ^n(e+f x) (d \sec (e+f x))^n\right ) \int \frac {\cos ^{1-n}(e+f x)}{b+a \cos (e+f x)} \, dx\\ &=-\left (\left (a \cos ^n(e+f x) (d \sec (e+f x))^n\right ) \int \frac {\cos ^{2-n}(e+f x)}{b^2-a^2 \cos ^2(e+f x)} \, dx\right )+\left (b \cos ^n(e+f x) (d \sec (e+f x))^n\right ) \int \frac {\cos ^{1-n}(e+f x)}{b^2-a^2 \cos ^2(e+f x)} \, dx\\ &=-\frac {\left (a \cos ^{2 \left (\frac {1}{2}-\frac {n}{2}\right )+n}(e+f x) \cos ^2(e+f x)^{-\frac {1}{2}+\frac {n}{2}} (d \sec (e+f x))^n\right ) \text {Subst}\left (\int \frac {\left (1-x^2\right )^{\frac {1-n}{2}}}{-a^2+b^2+a^2 x^2} \, dx,x,\sin (e+f x)\right )}{f}+\frac {\left (b \cos ^2(e+f x)^{n/2} (d \sec (e+f x))^n\right ) \text {Subst}\left (\int \frac {\left (1-x^2\right )^{-n/2}}{-a^2+b^2+a^2 x^2} \, dx,x,\sin (e+f x)\right )}{f}\\ &=\frac {a F_1\left (\frac {1}{2};\frac {1}{2} (-1+n),1;\frac {3}{2};\sin ^2(e+f x),\frac {a^2 \sin ^2(e+f x)}{a^2-b^2}\right ) \cos (e+f x) \cos ^2(e+f x)^{\frac {1}{2} (-1+n)} (d \sec (e+f x))^n \sin (e+f x)}{\left (a^2-b^2\right ) f}-\frac {b F_1\left (\frac {1}{2};\frac {n}{2},1;\frac {3}{2};\sin ^2(e+f x),\frac {a^2 \sin ^2(e+f x)}{a^2-b^2}\right ) \cos ^2(e+f x)^{n/2} (d \sec (e+f x))^n \sin (e+f x)}{\left (a^2-b^2\right ) f}\\ \end {align*}
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Mathematica [B] Leaf count is larger than twice the leaf count of optimal. \(5280\) vs. \(2(192)=384\).
time = 24.33, size = 5280, normalized size = 27.50 \begin {gather*} \text {Result too large to show} \end {gather*}
Warning: Unable to verify antiderivative.
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Maple [F]
time = 0.09, size = 0, normalized size = 0.00 \[\int \frac {\left (d \sec \left (f x +e \right )\right )^{n}}{a +b \sec \left (f x +e \right )}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (d \sec {\left (e + f x \right )}\right )^{n}}{a + b \sec {\left (e + f x \right )}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\left (\frac {d}{\cos \left (e+f\,x\right )}\right )}^n}{a+\frac {b}{\cos \left (e+f\,x\right )}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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